One of New York’s most renowned spots for sushi, tuna crispy rice (if you know, you know), and hand rolls is opening its first-ever Broward location this October in Oakland Park. Bondi Sushi is set to make its Broward debut at 3329 N. Federal Hwy. on Wednesday, October 29, with a grand opening party featuring cocktails by Shinji’s, which is ranked among the top 100 cocktail bars on North America’s 50 Best Bars 2025 list.
When New Times broke the news that the sushi spot was expanding from New York City to Miami Beach in 2023, foodies went wild. Following the success of its Miami Beach location, two additional outposts were established, including Midtown and Brickell. Bondi grew popular amongst locals for its high-quality fish and laid-back Japanese dining style. Now, Broward folks will finally get to try it for themselves.
“Oakland Park represents a pivotal moment for Bondi; it’s not just a new location, it’s the next evolution of who we are as a brand,” says David Hess, CEO of Bondi Sushi. “We’ve taken everything our guests love about Bondi, the energy, the accessibility, the craft, and layered in a new level of creativity and refinement. From our expanded menu to the cocktail bar we built with Shinji’s, this space is designed to surprise and delight. We’re proud to bring this elevated Bondi experience to Broward County and continue growing with the incredible community in South Florida.”
- 2 South Florida Restaurants Among Best Hidden Gems in U.S.
From Sushi Rolls to Wagyu Sliders and Lobster Tacos
On the menu, guests can expect Bondi Sushi’s signature selection of hot izakaya-inspired dishes, nigiri, sashimi, signature sushi rolls, and hand rolls (temaki) available exclusively at the omakase bar. In addition to these Bondi classics, the Oakland Park location will debut a range of brand new dishes made exclusively for the city, including wagyu sliders, lobster tacos, and skewers such as scallops with chimichurri and botan ebi (a type of spot prawn found in the cold waters of the Pacific Ocean)…